Manual for Design and Detailings of Reinforced Concrete to Code of ...

Version 2.3 May 2008(i)Worked Example 3.11 – shear design without shear enhancement inconcreteSection : b = 400 mm;100A d = 700 − 40 −16= 644 mm; st= 1. 5 ; fcu = 35 MPa;bdV = 700 kN;vc13⎛ fcu⎞= 0.79⎜⎟⎝ 25 ⎠14⎛100A⎞s⎜⎟⎝ bvd⎠1314⎛ 400 ⎞⎜ ⎟⎝ d ⎠⎛ 400 ⎞where ⎜ ⎟⎠⎝ d3700×10v = = 2.72 MPa,400×644Asvb v − vc400 2.72 − 0.81= =s 0.87 f 0.87×460v1γm= 0.81MPa;be kept as unity for d > 400 .( ) ( )yv= 1.91; Use T12 – 200 c/c d.s.(ii)Worked Example 3.12 – shear design with shear enhancement inconcrete.Re Figure 3.25 in which a section of 0.75 m from a support, as a heavypoint load is acting so that from the support face to the point load alongthe beam, the shear is more or less constant at 700 kN.a v = 750700 kNd = 644T32Figure 3.25 – Worked Example 3.11Section : b = 400 mm; cover to main reinforcement = 40 mm;100A d = 700 − 40 −16= 644 mm; st= 1. 5 ; fcu = 35 MPa; V = 700 kN;bd13⎛ fcu⎞vc= 0.79⎜⎟⎝ 25 ⎠3.11.⎛100A⎞s⎜⎟⎝ bvd⎠1314⎛ 400 ⎞⎜ ⎟⎝ d ⎠1γm= 0.81MPa as in Worked Example39