Manual for Design and Detailings of Reinforced Concrete to Code of ...

diameter of bars as will be illustrated in the Worked Example 3.14.Version 2.3 May 2008shear rupturespiral face45 oy 10 .5Asv0.87 f y0 .5Asv0.87 f yMoment provided by thisstirrup in region X is0.5Asv0.87 f y y1. Totalnos. of stirrup within X isx 1 / s v . So total momentis 0.5A sv0.87f y y1x1/ svx1Ty145 o 1y 1xRegion YRegion X0.5Asv0.87 f yx 10 .5Asv0.87 f yMoment provided by thisstirrup in region Y is0.5Asv0.87 f yx1. Totalnos. of stirrup within Y isy 1 / s v . So total momentis 0.5A sv0.87f yx1y1/ svFigure 3.31 – Derivation of Formulae for torsional reinforcements3.9.5 Worked Example 3.14 – Design for T-beam against torsionA total torsion of T = 200 kNm on a T-section as shown in Figure 3.32 withan average vertical shear stress on the web of 0.82 N/mm 2 . The section is alsounder bending requiring flexural steel area of 2865 mm 2 at bottom. Concretegrade is 35.15004001000450Option AOption BFigure 3.32 – Section of a T section resisting torsion for Worked Example 3.14100As2865×100For vertical shear, taking = = 0. 477b d 450×1334v45