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Phase diagrams of a two-dimensional Heisenberg antiferromagnet ...

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B.V. Costa, A.S.T. Pires / Journal <strong>of</strong> Magnetism and Magnetic Materials 262 (2003) 316–324 323procedure does not work. Making use <strong>of</strong> thetranslational invariance <strong>of</strong> the system we maydefine the Fourier transformsGðq; oÞ ¼ X m;n0S þ n ; S m Teiqðn mÞ ; ð28Þin terms <strong>of</strong> which Eq. (27) becomesGðq; oÞ ¼ /Sz S 1p o oðqÞ ; ð29ÞwhereoðqÞ ¼8/S z S½Jð1 g q ÞþD eff Š; ð30Þis the magnon energy spectrum and g q was definedin (9). Using the relation/ABS ¼ lime-0iZ þNNGðo þ ieÞ Gðo ieÞdo;expðboðqÞÞ 1ð31Þwe find the following expression for the magnetization:1/S z S ¼ S Z ð2pÞ 2 coth boðqÞ dq 2 :ð32Þ2Near the critical temperature, where /S z S goes tozero, we can expand the argument in the integraland obtain1¼ 1 Z1 d 2 qT c 4S 2p 2 : ð33ÞJð1 g q ÞþD effPerforming the integral in the q y variable, we find1¼ 1 Z1 pdq xq ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiT c 4JS 2p 2 ; ð34Þ0ð2 þ B cosq x Þ 2 1where B ¼ 2D eff =J: For B small we can solve theintegral analytically and obtain1¼ 1 T c 4JSp ln p : ð35ÞBBefore interpreting the data for Rb 2 MnF 4 let usapply Eq. (34) to <strong>two</strong> other compounds [22]. ForK 2 MnF 4 we have J ¼ 8:4K; D ¼ 0:134 K whichleads to T c ¼ 42:73 K: The experimental value is42:3K: The second compound is MnðHCOOÞ 2 2H 2 O: We have J ¼ 0:70 K; D ¼ 0:0114 K: Wefind T c ¼ 3:57 K; to be compared with the experimentalvalue 3.68 K. Just for comparison, thequantum SCR gives T c ¼ 42:19 K and T c ¼ 4:09 Krespectively. For Rb 2 MnF 4 ; if we take D temperaturedependent, using for D the effective anisotropydefined in Eq. (2) with H sf given by Eq. (22)and calculate T c using Eq. (34) we obtain T c ¼40:53 K: Otherwise using the temperature independentvalue for the anisotropy, D ¼ 0:148 K; wefind T c ¼ 38:73 K; to be compared with theexperimental value 38:4K:In the Ising region are seen deviations from thecalculations. This can be attributed to the destruction<strong>of</strong> the pure planar anisotropy in the high fieldphase. The 2D XYphase is extremely sensitive tosymmetry breaking interactions and to the interplanarcoupling. Any <strong>of</strong> these effects move thebicritical point from T ¼ 0 to a non-zero temperature.The interplanar coupling is <strong>of</strong>ten sosmall that the observed transition is primarilyinduced by anisotropy. The experimental data areconsistent with a BCP at a temperature near 30 K.Let us consider an orthorhombic anisotropy:this would correspond to Hamiltonian (1) with anadditional small anisotropy term D x ðSn xÞ2 : ForHoH sf the effective anisotropy is <strong>of</strong> the Ising-typeand the behavior is comparable to the uniaxialcase. Let us take H ¼ H eff ; use the experimentalvalue T c ¼ 30 K and determine the value <strong>of</strong> theparameter D x : For a positive D x a Kosterlitz–Thouless transition should occur at the bicriticalpoint T bc ¼ 30 K if D x ¼ 0:0212 K: Otherwise anegative term would lead to an order–disorder(Ising) transition with D x ¼ 0:028 K: An interplanarcoupling J 0 ; treated by the Green functionmethod, would have to have the value a ¼ J 0 =J ¼0:01; to give T bc ¼ 30 K; a value too high since it isexpected that a should be around 10 6 : We remarkthat this last value <strong>of</strong> a leads to T bc ¼ 12:5K: Thedashed line in Fig. 5 describes the result consideringinterplanar coupling with a ¼ 0:01: A similarcurve would be obtained in the case <strong>of</strong> anorthorhombic anisotropy. Here we have used thevalues <strong>of</strong> J and D given in Ref. [1]. Theexperimental data <strong>of</strong> those authors differ slightlyfrom the ones obtained by Cowley et al. [16]. Ofcourse we could vary D and D x to get a better fit to

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