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Modeling Tools for Environmental Engineers and Scientists

Modeling Tools for Environmental Engineers and Scientists

Modeling Tools for Environmental Engineers and Scientists

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Hence, Q π tan–1 – 1 – UL – 1Q/2f r = 2 9 = = π2 tan –1 – 1 – – 1 The above can be solved by trial <strong>and</strong> error to find as = 2.3, <strong>and</strong> hence, Lfrom L = Q/(π U) as L = 553 ft. Hence, the well can be as close as 600 ft tothe river <strong>and</strong> meet the water quality st<strong>and</strong>ard.A plot of the stream function can illustrate the above concepts visually.The composite stream function <strong>for</strong> this problem can be <strong>for</strong>mulated by addingthe stream functions <strong>for</strong> a uni<strong>for</strong>m flow field representing the aquifer, asource representing the proposed well, <strong>and</strong> a sink representing the image well. = Uy + 2Qπ θ 1 – 2Qπ θ 2Q= Uy + 2π tan–1 x –y QL – 2π tan–1 x yL The Mathematica ® model of this problem to generate the streamlines <strong>and</strong> thevelocity potentials is shown in Figure 9.38 <strong>for</strong> L = 600 ft.As a comparison, the streamlines, velocity potentials, <strong>and</strong> combined plots<strong>for</strong> the “safe” case with = 1 or L = 1300 ft are shown in Figure 9.39.Figure 9.38a Script <strong>for</strong> stream lines <strong>and</strong> velocity potentials in Mathematica ® .© 2002 by CRC Press LLC

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