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Modeling Tools for Environmental Engineers and Scientists

Modeling Tools for Environmental Engineers and Scientists

Modeling Tools for Environmental Engineers and Scientists

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The given value of K a–w indicates that the gas phase content is quantifiedin partial pressure (atm.), <strong>and</strong> the aqueous phase content is quantified bymole fraction (mole/mole). Oxygen content in the atmosphere = 21% =mole fraction of 0.21. Because the atmospheric pressure is 1 atm., usingDalton’s Law, the partial pressure of oxygen in air = 0.21 × 1 atm.= 0.21 atm.0.21 atm.∴ Oxygen content in water = 40,000 atm .-molesHm 2OolesO= 5.25 × molesO10–6 2 m olesH O g2= 5.25 × 10 –6 molesO2m olesH O32g O2mg olesmoleO 1000 g m 18g H2O0gH O 100L = 9.3 m gL(2) In the given K a–w value, the gas phase content is in partial pressure <strong>for</strong>m,<strong>and</strong> the aqueous phase content is in the mole fraction <strong>for</strong>m. To convertthis value to the mole concentration ratio <strong>for</strong>m, the gas phase content hasto first be converted from the partial pressure <strong>for</strong>m to the molar concentration<strong>for</strong>m (moles/L). This can be achieved using the Ideal Gas Law:2222or,pV nRTn p R V TAssuming ambient temperature of T = 25ºC, <strong>and</strong> R = 82 atm.-L/kmole-K, at the partial pressure = 0.21 atm.,n 0.21 atm. V atm.-L82 k(273 + 25)Kmole-K= 8.6 × 10–6 km oleL = 8.6 × 10 –3 m oleLThe mole fraction in the aqueous phase was found as 5.25 × 10 –6 in part(I), which can be converted to molar concentration C using Equation(4.15):C A = X × C = (5.25 × 10 –6 ) × 55.5 gm oleL = 2.9 gm oleL© 2002 by CRC Press LLC

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