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v2007.09.17 - Convex Optimization

v2007.09.17 - Convex Optimization

v2007.09.17 - Convex Optimization

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3.1. CONVEX FUNCTION 199orthonormal matrices W = UU T where U T U = I as explained inE.3.2. From (1639) for any ǫ > 0 and idempotent symmetric W ,ǫ(W + ǫI) −1 = I − (1 + ǫ) −1 W from whichThereforef(W , x) = ǫx T (W + ǫI) −1 x = x T( I − (1 + ǫ) −1 W ) x (473)limǫ→0 +f(W, x) = lim (W + ǫI) −1 x = x T (I − W )x (474)ǫ→0 +ǫxTwhere I − W is also an orthogonal projector (E.2).We learned from Example 3.1.7.0.4 that f(W , x)= ǫx T (W +ǫI) −1 x isconvex simultaneously in both variables over all x ∈ R n when W ∈ S n + isconfined to the entire positive semidefinite cone (including its boundary). Itis now our goal to incorporate f into an optimization problem such thatan optimal solution returned always comprises a projection matrix W . Theset of orthogonal projection matrices is a nonconvex subset of the positivesemidefinite cone. So f cannot be convex on the projection matrices, andits equivalent (for idempotent W )f(W , x) = x T( I − (1 + ǫ) −1 W ) x (475)cannot be convex simultaneously in both variables on either the positivesemidefinite or symmetric projection matrices.Suppose we allow domf to constitute the entire positive semidefinitecone but constrain W to a Fantope (79); e.g., for convex set C and 0 < k < nas inminimize ǫx T (W + ǫI) −1 xx∈R n , W ∈S nsubject to 0 ≼ W ≼ I(476)trW = kx ∈ CAlthough this is a convex problem, there is no guarantee that optimal W isa projection matrix because only extreme points of a Fantope are orthogonalprojection matrices UU T .Let’s try partitioning the problem into two convex parts (one for x andone for W), substitute equivalence (473), and then iterate solution of convexproblem

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