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Advanced Calculus fi..

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288 <strong>Advanced</strong> <strong>Calculus</strong>. Fifth EditionFigure 5.14Construction of function F such that dF = P dx + Q dy.THEOREM I If the integral P dx + Q dy is independent of path in D, thenthere is a function F(x, y) de<strong>fi</strong>ned in D such thatholds throughout D. Conversely, if a function F(x, y) can be found such that (5.46)holds in D, then j" P dx + Q dy is independent of path in D.Proof. Suppose <strong>fi</strong>rst that the integral is independent of path in D. Then choose apoint (xo, yo) in D and let F(x, y) be de<strong>fi</strong>ned as follows:dwhere the integral is taken on an arbitrary path in D joining (xO, yo) to (x, y).Since the integral is independent of path, the integral in (5.47) does indeed dependonly on the endpoint (x, y) and de<strong>fi</strong>nes a function F(x, y). It remains to show thata~lax = P (X, y), a~lay = Q(X, y) in D.For a particular (x, y) in D, choose ( XI, y) so that xl # x and the line segmentfrom (xl, y) to (x, y) is in D, as shown in Fig. 5.14. Then, because of independenceof path, one hasHere xl and y are thought of as <strong>fi</strong>xed, while (x, y) may vary along the line segment.Thus y has been restricted to a constant value, and F(x, y) is being considered asa function of x near a particular choice of x. The <strong>fi</strong>rst integral on the right is thenindependent of x, while the second can be integrated along the line segment. Hencefor this <strong>fi</strong>xed y,or, with the dummy variable x replaced by a t,F(x, y) = const + P(t, y)d't.1:

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