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Advanced Calculus fi..

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474 <strong>Advanced</strong> <strong>Calculus</strong>, Fifth EditionHence for 0 < Ix 10< n;:~i !4 4 . 4 " sin (2n - 1)x., f(x)= -sinx+-sin3x+...=-~n 3nn=l2n-1 'The <strong>fi</strong>gure shows the <strong>fi</strong>rst three partial sums4 4 4 .S1=-sinx, S2=S1+-sin3x, S3=S2+-sinkn 3n 5nof this series. If the graphs are studied carefully, then it becomes clear that f (x) isbeing approached as limit. For x = 0, each partial sum equals 0, so that the seriesdoes converge to the average value at the jump; there is a similar situation at x = f n.However, it should be noted that the approximation to f (x) by each partial sum ispoorest immediately to the left and right of the jump points.EXAMPLE 2 Let f (x) = in + x for -n 5 x 5 0 and f (x) = in - x for0 i x 5 n. The periodic extension of f (x) is the "triangular wave" of Fig. 7.6. Inthis example the extended function is continuous for all x. One <strong>fi</strong>ndsa,, = IS0 n -, (;+x)cosnxdx+- o (5- X) cos nx cix1"1 2= [i(l - cosnn) + -(I - cosnn) = -(I - cosnn)n n2 n2 ] n2nfor n = 1,2, . . . . For n = 0 a separate computation is needed:The computation of the b,'s is like that of the an's, and one <strong>fi</strong>nds b, = 0 forn=l,2, .... Hence4 4 4 " cos (2n - l)xf(x)= -cosx+-cos3x+~~~=-Cn 9n (2n -IT n=1The <strong>fi</strong>rst two partial sums are plotted in Fig. 7.6. Since there are no jumps, one mustexpect convergence everywhere. It should, however, be noted that at the corners(where f '(x) has a jump), the convergence is poorer than elsewhere.Thus far we have proceeded formally, evaluating coef<strong>fi</strong>cients and verifyinggraphically that the series converges to the function. We now proceed to examinethe steps more carefully.The constant term ao/2 of the series is given by the formula

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