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Advanced Calculus fi..

Advanced Calculus fi..

Advanced Calculus fi..

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Chapter 6 In<strong>fi</strong>nite Series 381Every sequence will then possess upper and lower limits. It should be noted thatwhen lim s, = -oo, the upper and lower limits are both -oo. In general, the lowerlimit cannot exceed the upper limit.THEOREM 3 If the sequence s, converges to s, then-lim sn = !@ s, = s;n+oc n+ccconversely, if upper and lower limits are equal and <strong>fi</strong>nite, the sequence converges. 1The <strong>fi</strong>rst part of the theorem follows from the de<strong>fi</strong>nition of convergence; forthe limit s satis<strong>fi</strong>es all conditions for both upper and lower limits. If the upper andlower limits are both <strong>fi</strong>nite and equal to s, the sequence is necessarily bounded, forotherwise the upper limit would be +oo or the lower limit would be -00. If s, doesnot converge to s, then for some E there are in<strong>fi</strong>nitely many members of the sequencesuch that Is, - s I > E . One can then proceed as in the proof of Theorem 1 to producea limiting value k other than s. This contradicts the fact that s is both the largest and .least limiting value.We <strong>fi</strong>rst point out connections between sequences and continuity of functions. 3msTHEOREM 4xo, thenLet y = f (x) be de<strong>fi</strong>ned for a 5 x 5 b. If f (x) is continuous ati tfor every sequence x, in the interval converging to xo. Similarly, iff (x, y) is de<strong>fi</strong>nedin a domain D and is continuous at (xO, yo), thenfor all sequences x, , y, such that (x, , yn) is in D and x, converges to xo, y, convergesto Yo.We prove the statement for f (x), the proof for a function of two (or more)variables being similar. Given E > 0, a 8 can be found such that If(x)- f (xo)l < E forIx -xo I < 8; this is simply the de<strong>fi</strong>nition of continuity. One can then choose N so thatIx, -xol < 6 for n > N, sincex, converges toxo. Accordingly, I f (x,,) - f (xo)l < 6for n > N; that is, f (x,) converges to f (xo).We remark that there is a converse to Theorem 4: If f (x) has the property thatf (x,,) converges to f (xo) for every sequence x, that converges to xo, then f (x) mustbe continuous at xo (Theorem G in Section 2.23).. . - I

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