applied fracture mechanics

Good Practice for Fatigue Crack Growth Curves Description 215and is easily solved by subtracting in the following steps:- eliminating b0n n 21 f n n n n1, if1, if 1, i f2, if1, if2,inn 2 2 2 2 2i1yi i1 yi i1 yi i1 yi i1 yi i1yi bn n 1 n n b2n n1 f1, i 1 f 1, i 1 f 1, i 2 2 2 2 2 2i 1yi i 1 y i i1yi i1 y i i1yi i1y i n f n3, if1, if3,i2 2 i1yii1yib3 0,nn1 f 1, i 2 2i1yii 1 y i n n 21 f n n n n2, i f1, if1, if2, i f2, if 2, inn 2 2 2 2 2i1yi i1 yi i1 yi i1 yi i1 yi i1y i bn n 1bn n 2 n1 f 2, i 1 f n 2, i 1 f2, i 2 2 2 2 2i1yi i1 y i i1yi i1 y 2i i1yi1 y ii n f n3, if2, if3,i2 2 i1 yii1yib3 0,nn1 f 2, i 2 2i 1yii 1 y i n n n n1 f3, i f1, if1, if3,i n f n2, if2, if3,inn 2 2 2 2 2i1yi i1 yi i1 yi i1yi i1 yii1yi bn n 1n n1 f 3, i 1 f b2 nn3, i1 f 3, 2 2 2 2i1yi i1 y i2 2i i1yi i1y i i 1yii 1 y i n n 2f3, if 3, i2 2 i1 yii1y ib3 0n n 1 f3,i 2 2i1yii1y i (26)what gives 3 equations of the general form:Bk bB1 1, kbB 2 2, kbB3 3, k0k 1,2,3.(27)- eliminating b1