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PDF document - Orbital and Celestial Mechanics Website

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EE0 ecos cos2 2EE0 sin sin2 2the time equation becomesFrom the elliptic relationships given by3a t 2sin cos 2 2 r a 1ecosEx a cos E ey a sin E 1e2<strong>and</strong> some more manipulation, we have the following equations: r r c r r c s 2a 2a 2a a0 0cos1 1 1 r r c r r c s c 2a 2a 2a a0 0sin 1 1 1This part of the derivation makes use of the following three relationships: rrcos cos 12 2 202E E0 E E0 e sin sin sin 1 cos2 2 2 22 2 2 2x x0 y y0c sinsin 2 2 2a 2a 2aWith the use of the half angle formulas given bysins sins c2 2a2 2a<strong>and</strong> several additional substitutions, we have the time-of-flight form of Lambert’s theorempage 17

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