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COPYRIGHT 2008, PRINCETON UNIVERSITY PRESS

COPYRIGHT 2008, PRINCETON UNIVERSITY PRESS

COPYRIGHT 2008, PRINCETON UNIVERSITY PRESS

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fourier analysis: signals and filters 235(10.8) determines the values⇒b n = 2 Ty(t)= 2 π∫ +T/2−T/2tdt sin nωtT/2 = ω π[sin ωt − 1 2 sin 2ωt + 1 3∫ +π/ω−π/ωdt sin nωt ωtπ = 2nπ (−1)n+1 ,sin 3ωt −···]. (10.14)10.2.2 Example 2: Half-wave FunctionThe half-wave function⎧⎨sin ωt, for 0

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