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Passive, active, and digital filters (3ed., CRC, 2009) - tiera.ru

Passive, active, and digital filters (3ed., CRC, 2009) - tiera.ru

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Single-Amplifier Multiple-Feedback Filters 12-7Example 12.2Design the MFB b<strong>and</strong>pass filter characterized in Example 12.1 as a high-pass=low-pass cascade ofsecond-order sections. Use the design equations of Table 12.2 <strong>and</strong>, where possible, set capacitorsequal to 5600 pF. It is suggested that you use the same impedance denormalization factor in eachstage. Select the nearest preferred 1% resistor values.SolutionSince the peak gain of the overall cascade is to be 10, let this also be the gain of stage 1 (this solutionyields the best noise performance). The peak gain of the low-pass section is given byH 1 Qpffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi¼ 7:16H 1 ¼ 10 \ H 1 ¼ 1:3971 1=2Q 2The overall transfer function (from Example 12.1) isV o0:4s 2¼V i s 4 þ 0:2824s 3 þ 2:04s 2 þ 0:2824s þ 1\ H 1 H 2 ¼ 0:4 so that H 2 ¼ 0:286Thus, assuming a low-pass=high-pass cascade, we haveV o 1:397¼V i s 2 þ 0:15145 þ 1:1522 0:286s 2s 2 þ 0:1314s þ 0:8679section 1 section 2Design the low-pass section (section 1) using Table 12.2 to yieldH 1G 1 ¼ pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi¼ 1:301, so that R 1 ¼ 0:7684 V1:15218 2v 2 p þ H 1C 2 ¼Q p ¼ 22:77 Fv 2 pG 3 ¼ v p ¼ 1:0733, so that R 3 ¼ 0:9316 V ¼ R 4C 5 ¼ 1=C 2 ¼ 0:0439 FNow, design the high-pass section (section 2) to yieldC 0 1 ¼ 0:286 FG 0 2 ¼ v pð2 þ H 2 ÞQ ¼ 15:099, so that R 0 2 ¼ 0:0662 VC3 0 ¼ C0 4 ¼ 1FG 0 5 ¼ v pQ p (2 þ H) ¼ 0:0574,so that R0 5 ¼ 17:397 VTo obtain as many 5600 pF capacitors as possible, the two sections should be denormalized separately.However, in this example, a single impedance denormalization will be used. Setting C3 0 ¼ C0 4¼ 5600 pFyields z n ¼ 18,947.

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