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Passive, active, and digital filters (3ed., CRC, 2009) - tiera.ru

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1-D Multirate Filter Banks 24-25duration is infinite. For the causal stable case the function extends to positive infinity <strong>and</strong> for thenoncausal case the function extends to infinity in both directions.A versatile building block for IIR <strong>filters</strong> is the all-pass filter a(z) which has the following two properties:1a(z) ¼ a(z 1 ) <strong>and</strong> ja(e jv )j¼1 (24:68)The all-pass filter a(z) can be considered a generalization of the unit delay z 1 since je jv j¼ja(e jv )j¼1,i.e., both have the same magnitude response. The unit delay has a linear phase response but the all-passfilter can have a variety of phase responses. A wide family of IIR <strong>filters</strong> can be obtained by variousinterconnections of all-pass <strong>filters</strong> [7–9]. The simplest interconnection (described below) can give a largeclass of useful IIR filter banks.24.7.1 All-Pass Filter Design MethodsConsider analysis <strong>filters</strong> obtained by the weighted sum <strong>and</strong> difference of two all-pass <strong>filters</strong>, a 0 <strong>and</strong> a 1 :H 0 (z) ¼ p 1 ffiffi [a 0 (z) þ a 1 (z)]2H 1 (z) ¼ p 1 ffiffi [a 0 (z)2a 1 (z)](24:69)This can be considered an extension of the FIR Haar filter pair in Equation 24.2 to IIR <strong>filters</strong>. The terms 1<strong>and</strong> z 1 (simple all-pass) have been replaced with a 0 <strong>and</strong> a 1 , general all-pass <strong>filters</strong>. The Haar <strong>filters</strong> arequadrature mirror versions of each other. If the two all-pass <strong>filters</strong> are chosen to be of the forma 0 (z) ¼ A 0 (z 2 ), a 1 (z) ¼ z 1 A 1 (z 2 ), then the analysis <strong>filters</strong>, given byH 0 (z) ¼ 1 pffiffiA 0 (z 2 ) þ z 1 A 1 (z 2 )2H 1 (z) ¼ 1 pffiffiA 0 (z 2 ) z 1 A 1 (z 2 )2(24:70)will have the quadrature mirror characteristics:jH 1 (e jv )j¼jH 0 (e j(p v) )j, i.e., be mirrored about v ¼ p 2(24:71)This means that if H 0 (e jv ) has a low-pass frequency response, H 1 (e jv ) will automatically have a high-passresponse.How should the all-pass <strong>filters</strong> be designed so that H 0 (e jv ) is a good low-pass filter with half of the fullb<strong>and</strong>width?By denoting the phase response of the all-pass <strong>filters</strong> as f 0 (v) ¼ffA 0 (e jv ) <strong>and</strong> f 1 (v) ¼ffA 1 (e jv ), themagnitude response of the low-pass filter can be written asjH 0 (e jv )j¼ 1 pffiffie jf0(2v) þ e j(f 1(2v) v) 2¼ 1 pffiffie jf 0(2v) 1 þ ej(f 1 (2v) f 0 (2v) v) 2¼ 1 pffiffi j(u(2v) v)1 þ e where u(v) f 1 (v) f 0 (v) (24:72)2

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