KITUI SAND DAMS

Number of rings per evaragecolumns.De De= = = 2DeSpacing 0.5Total length of R6.25=Length per Ring x No of Rings peraverage column x No of columns.Ld=1.6(2De+1)( 12 − )Ld= 1 .6( DeLd − 2De+ + 1)2No of R6.251. 6Ld= ( DeLd − 2De+ + 1)12 2Example.L d =20, D e =20.20=0.13 ( 20x2) − (2x2)− + 1)2=(5.2 –0.52+1.3+0.13)=6.11NB: 0.13 can be Negligible.HenceNo of R 6.25=Ld0.13 ( DeLd − 2De− −1)2Ld=0.13 ( DeLd − 2De+ + 1)2e) Barbed Wire.Gauge 16, Length=610m, Spacing= 0.45Average strands=10Total length of barbed wire= 10 x LdDeNo of layers of Barbed wire = 0.4510Ld.DeTotal length of Barbed wire =0.45Example.L d =20, D e =2No of rolls of barbed wire= 0.4 x 20 x 2= 1.6No of rolls of Barbed wire =10Ld.De0.45x610No of rolls of Barbed wire = 0.04L d D e63