Advanced Bash−Scripting Guide

The multiplication operator must be escaped when used in an arithmetic expression with
expr.
y=`expr $y + 1`
Increment a variable, with the same effect as let y=y+1 and y=$(($y+1)). This is an
example of arithmetic expansion.
z=`expr substr $string $position $length`
Extract substring of $length characters, starting at $position.
Example 12−6. Using expr
Advanced Bash−Scripting Guide
#!/bin/bash
# Demonstrating some of the uses of 'expr'
# =======================================
echo
# Arithmetic Operators
# −−−−−−−−−− −−−−−−−−−
echo "Arithmetic Operators"
echo
a=`expr 5 + 3`
echo "5 + 3 = $a"
a=`expr $a + 1`
echo
echo "a + 1 = $a"
echo "(incrementing a variable)"
a=`expr 5 % 3`
# modulo
echo
echo "5 mod 3 = $a"
echo
echo
# Logical Operators
# −−−−−−− −−−−−−−−−
# Returns 1 if true, 0 if false,
#+ opposite of normal Bash convention.
echo "Logical Operators"
echo
x=24
y=25
b=`expr $x = $y`
# Test equality.
echo "b = $b" # 0 ( $x −ne $y )
echo
a=3
b=`expr $a \> 10`
echo 'b=`expr $a \> 10`, therefore...'
echo "If a > 10, b = 0 (false)"
echo "b = $b" # 0 ( 3 ! −gt 10 )
echo
Chapter 12. External Filters, Programs and Commands 155