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Alevel_C1C2

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4<br />

Exam-style mark scheme<br />

Quadratic and linear relationships<br />

Question Scheme Marks<br />

Number<br />

1. (a) x = 5 - 4y, substitute x = 5 - 4y in 3x + 2y = -5<br />

15 − 12y + 2y = -5 B1oe<br />

10y = 20<br />

y = 2 and x = -3 A1 A1ft (3)<br />

(b) y = 2x + 3 B1<br />

2x 2 + 5x + 3(1 + 2x + 3) = 0<br />

B1<br />

2x 2 + 11x + 12 = 0<br />

(2x + 3)(x + 4) = 0 M1<br />

x = − 3 ⇒ y = 0<br />

2<br />

A1 A1ft<br />

x = −4 ⇒ y = −5 A1 A1ft (5)<br />

8<br />

2.<br />

y<br />

–2<br />

O<br />

3<br />

x<br />

B2 B1<br />

y – x + 3 = 0<br />

–3<br />

y = (x – 3)(x + 2)<br />

(-2, 0), (3, 0), (0.5, -6.25) minimum A4<br />

(-1, -4), (3, 0) A2<br />

9<br />

3. (a) 6x + 2 - 8x + 12 > 0 B1<br />

14 > 2x A1 (2)<br />

x < 7<br />

(b)<br />

y<br />

O<br />

1<br />

2<br />

x<br />

B2<br />

3y = 2x – 1<br />

– 1 3<br />

B1 (3)<br />

5<br />

© Oxford University Press 2008<br />

Core C1

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