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The Tough Stuff Made Easy: Advanced Multiplication 187<br />

For example, in the problem above, 900 829 1729 just as<br />

876 853 1729. This is because:<br />

z [(z a) b] (z a) (z b)<br />

Thus, to obtain the number to be multiplied by 900 (which<br />

you know will be 800 plus something), you need only look at<br />

the last two digits <strong>of</strong> 76 53 129 to determine 829.<br />

In the next problem, adding 827 761 1588 tells us that<br />

we should simply multiply 800 788, then subtract 27 39 as<br />

follows:<br />

827 (27)<br />

<br />

<br />

761 (39)<br />

800 788 630,400<br />

39 27 1,053 (39 9 3)<br />

<br />

629,347<br />

This method is so effective that if the 3-by-3 problem you are<br />

presented with has numbers that are not close together, you can<br />

sometimes modify the problem by dividing one and multiplying<br />

the other, both by the same number, to bring them closer together.<br />

For instance, 672 157 can be solved by:<br />

672<br />

157<br />

<br />

2 <br />

2 <br />

336 (36)<br />

314 (14)<br />

<br />

300 350 105,000<br />

36 14 504<br />

<br />

105,504<br />

(36 7 2)<br />

When the numbers being multiplied are the same (you can’t<br />

get any closer than that!), notice that the close-together method

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