BÀI GIẢNG HÓA PHÂN TÍCH TS. GVC. HOÀNG THỊ HUỆ AN
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Ví dụ : Chuẩn độ dd Fe 2+ 0,1 N bằng dd KMnO 4<br />
0,1 N ở pH = 0<br />
Cho biết : E 0 MnO4-,/Mn2+ (pH = 0) = 1,51 V ; E 0 Fe 3+/Fe 2+ = 0,77 V<br />
F<br />
0,999<br />
1,000<br />
1,001<br />
E<br />
E<br />
E<br />
Công thức tính E<br />
0<br />
= EFe3+<br />
/ Fe2+<br />
0<br />
1. E Fe + / Fe2+<br />
+ 5. E<br />
6<br />
F<br />
+ 0,059lg<br />
(1 − F)<br />
0<br />
=<br />
3 MnO4−/<br />
Mn2+<br />
0,059<br />
+ lg( F<br />
5<br />
0<br />
= EMnO<br />
4−/<br />
Mn2<br />
+<br />
−<br />
1)<br />
E (V)<br />
0,95<br />
1,39<br />
1,48<br />
E<br />
1.6<br />
1.4<br />
1.2<br />
1<br />
0.8<br />
0.6<br />
0 0.5 1 1.5 2 F<br />
Để sai số chuẩn độ không quá 0,1%, thì : E kt ∈ ∆E đp<br />
E kt = 0,95 ÷ 1,48 (V)
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