BÀI GIẢNG HÓA PHÂN TÍCH TS. GVC. HOÀNG THỊ HUỆ AN
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Giải :<br />
Hệ số chuyển của P và của P 2 O 5 là :<br />
f<br />
P<br />
=<br />
2. M<br />
M<br />
Mg<br />
2<br />
P<br />
P<br />
2<br />
O<br />
7<br />
=<br />
2.30,97<br />
222 ,55<br />
≈<br />
0,2783<br />
f<br />
2. M<br />
M<br />
2<br />
2<br />
7<br />
2.141,95<br />
222 ,55<br />
P 2O<br />
5<br />
P 2O<br />
5<br />
= = ≈<br />
Mg P O<br />
1,2757<br />
mc<br />
0,4320<br />
% P = f<br />
P.<br />
.100% = 0,2783 . .100% ≈<br />
a<br />
0,7030<br />
17,10%<br />
0,4320<br />
% . mc<br />
P2 O5<br />
= f<br />
P 2O<br />
5<br />
.100% = 1,2757 . .100% ≈<br />
a<br />
0,7030<br />
78,39%
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