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BÀI GIẢNG HÓA PHÂN TÍCH TS. GVC. HOÀNG THỊ HUỆ AN

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Giải :<br />

Bảng số liệu<br />

Phương trình đường chuẩn :<br />

A = 0,1819C – 0,0012<br />

Nồng độ Fe trong dd đo quang :<br />

C<br />

Fe(dd đo)<br />

≈ 1,49 ppm<br />

Hàm lượng Fe trong mẫu nước thải phân tích :<br />

C<br />

=<br />

A<br />

đo<br />

1,48.50<br />

10<br />

+ 0,0012<br />

0,1819<br />

Fe ( ddpt )<br />

= 7, 45<br />

0,269 + 0,0012<br />

=<br />

0,1819<br />

ppm<br />

A<br />

0.800<br />

0.600<br />

0.400<br />

0.200<br />

0.000<br />

Đường chuẩn Fe y = 0.1819x - 0.0012<br />

R 2 = 0.9999<br />

0.00 2.00 4.00 6.00<br />

Fe (ppm)

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