trigonometry
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162 GEOMETRY AND TRIGONOMETRY<br />
Problem 19. Use harmonic synthesis to construct<br />
the complex current given by:<br />
i 1 = 10 sin ωt + 4 sin 2ωt amperes.<br />
Current i 1 consists of a fundamental component,<br />
10 sin ωt, and a second harmonic component,<br />
4 sin 2ωt, the components being initially in phase<br />
with each other. The fundamental and second harmonic<br />
are shown plotted separately in Fig. 15.33.<br />
By adding ordinates at intervals, the complex waveform<br />
representing i 1 is produced as shown. It is noted<br />
that if all the values in the negative half-cycle were<br />
reversed then this half-cycle would appear as a mirror<br />
image of the positive half-cycle about a vertical<br />
line drawn through time, t = T/2.<br />
Problem 20.<br />
given by:<br />
i 2 = 10 sin ωt + 4 sin<br />
Construct the complex current<br />
(<br />
2ωt + π )<br />
amperes.<br />
2<br />
The fundamental component, 10 sin ωt, and the second<br />
harmonic component, having an amplitude of<br />
4A and a phase displacement of π radian leading<br />
2<br />
(i.e. leading 4 sin 2ωt by π radian or T/8 seconds),<br />
2<br />
are shown plotted separately in Fig. 15.34. By adding<br />
ordinates at intervals, the complex waveform for i 2 is<br />
produced as shown. The positive and negative halfcycles<br />
of the resultant waveform are seen to be quite<br />
dissimilar.<br />
From Problems 18 and 19 it is seen that whenever<br />
even harmonics are added to a fundamental<br />
component:<br />
(a) if the harmonics are initially in phase, the negative<br />
half-cycle, when reversed, is a mirror image<br />
of the positive half-cycle about a vertical line<br />
drawn through time, t = T/2.<br />
(b) if the harmonics are initially out of phase with<br />
each other, the positive and negative half-cycles<br />
are dissimilar.<br />
These are features of waveforms containing the<br />
fundamental and even harmonics.<br />
Problem 21. Use harmonic synthesis to construct<br />
the complex current expression given by:<br />
(<br />
i = 32 + 50 sin ωt + 20 sin 2ωt − π )<br />
mA.<br />
2<br />
Figure 15.33