COAST. I ARTILLERY JOURNAL, - Air Defense Artillery
COAST. I ARTILLERY JOURNAL, - Air Defense Artillery
COAST. I ARTILLERY JOURNAL, - Air Defense Artillery
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432 THE <strong>COAST</strong> <strong>ARTILLERY</strong> <strong>JOURNAL</strong><br />
is provided with the Universal Measuring Camera after the manner of<br />
the theodolite.<br />
Figure 1 will serve to explain the method of computing the trajectory<br />
path s passed over by the projectile from the muzzle of the<br />
gun to the limit taken in by the sighting field of the instrument.<br />
Let: G = Gun muzzle = initial point of the distance measured<br />
M = Terminal point of measured distance m<br />
P = Position of camera<br />
PG = Measured distance between camera and gun muzzle<br />
HGM = Angle of elevation of gun = f3<br />
GPI = Terrain angle between camera and gun muzzle = y<br />
FIP = Angle between muzzle-camera line and firing<br />
direction = a<br />
GPM = Sight angle of the camera = e<br />
OPF = Inclination of the optical axis = 7r<br />
MGP = Auxiliary angle in.the triangle GPM = 8<br />
GOP = Auxiliary angle in the triangle GOP = w<br />
The pictured length of trajectory GM is computed by using the<br />
auxiliary angle 8. In order that the assumption upon which the measurements<br />
are based may actually obtain and the optical axis of the<br />
camera may intersect the trajectory at the point 0, it is necessary to<br />
compute also the angle 7r and to incline the object glass through this<br />
angle.<br />
The computation of the auxiliary angle 8 is most easily made by<br />
using the adjoining pyramid APIG. In the four triangles of this<br />
pyramid, let:<br />
AP=A GP=B DI=Rsing=D AG=Rsing/sinf3=C<br />
IP = Rcos g = B' AG = D/sin f3 = C AI =B. sin g. cos f3 = C'<br />
sin f3<br />
By application of the cosine proposition one now establishes a<br />
relation in the two triangles AGP and AlP between the four angles a,<br />
7r, g, and 8, namely:<br />
N= B2+ C:}- 2 BC. cos 1.l80 - 8)<br />
A2= B'2+ C'2_ 2 B' C'. cos (ISO - a)<br />
(1)<br />
(2)<br />
Equalizing (1) and (2) and introducing the angle functions in<br />
place of the triangle sides give:<br />
B o> 0> I B2 sin2 g cos 2 f3 2 BO> (180 cos f3 sin g cos g<br />
- cos- g.- sin:!f3 - cos -aJ sin f3 -<br />
B2-L B2sin 2 g 2 B2cos (ISO - 81 s~ f3g •<br />
I sin2 f3 ., Sill<br />
After multiplying through by sin 2 f3. B2 we isolate the member