12.07.2015 Views

Uždavinių pavyzdžiai (pdf)

Uždavinių pavyzdžiai (pdf)

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→Ar vektorinis laukas a( x z 2 − y 2 )→( ⋅ ⋅iy x 2 − z 2 →) ( + ⋅ j z y 2 − x 2 )→= + ⋅ ⋅ksolenoidinis?div a = 0 solenoidinis⋅( )⋅( )P := x z 2 − y 2 Q := y x 2 − z 2 R := z⋅( y 2 − x 2 )∂P∂x→z 2 − y 2∂Q∂y→x 2 − z 2∂R∂z→y 2 − x 2div a∂:=∂P +∂Q + R → 0 vektorinis laukas∂x∂y∂zsolenoidinis

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