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Linear Algebra - Sebastian Pancratz

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vi λik = 0 1 ≤ i ≤ m <br />

1 ≤ k ≤ n εij <br />

α ∈ L(U, V ) α(uk) = <br />

i aikvi <br />

<br />

(aijεij(uk)) = <br />

aikvi = α(uk)<br />

i,j<br />

1 ≤ k ≤ n U <br />

<br />

<br />

m × n F A = (aij) m n <br />

aij ∈ F 1 ≤ i ≤ m 1 ≤ n ≤ n Mm,n(F) m × n <br />

F<br />

Mm,n(F) <br />

dimF Mm,n(F) = mn<br />

(aij) + (bij) = (aij + bij)<br />

λ(aij) = (λaij)<br />

1 ≤ i ≤ m 1 ≤ j ≤ n <br />

<br />

eij = 1<br />

Eij =<br />

<br />

i<br />

ei ′ j ′ = 0 (i′ , j ′ ) = (i, j).<br />

U V F α : U → V <br />

B = {u1, . . . , un} C = {v1, . . . , vm} U V A = (aij) <br />

α(uj) = <br />

i aijvi u ∈ U u = <br />

i λiui [u]B = (λ1, . . . , λn) T <br />

A = <br />

[α(u1)]C · · · [α(un)]C ,<br />

A = [α]B,C<br />

u ∈ U [α(u)]C = [α]B,C[u]B<br />

u ∈ U u = <br />

j λjuj [u]B = (λ1, . . . , λn) T <br />

α(u) = <br />

λjα(uj)<br />

[α(u)]C = A · [u]B<br />

j<br />

= <br />

j<br />

λj<br />

= <br />

i<br />

j<br />

<br />

i<br />

aijvi<br />

aijλjvi<br />

= <br />

(A · [u]B)ivi<br />

i

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