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Taylorpolynomier Funktion af flere variable

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<strong>Funktion</strong> givet ved simpel forskrift<br />

I f (x) = x arctan x med udviklingspunkt 1, orden 2.<br />

I Vi har<br />

f 0 (x) = arctan x + x<br />

1 + x 2<br />

f 00 2 2x<br />

(x) =<br />

2<br />

1 + x 2 (1 + x 2 ) 2<br />

I Så f (1) = π 4 , f 0 (1) = π 4 + 1 2 , f 00 (1) = 1 2 .<br />

<strong>Taylorpolynomier</strong>.<br />

<strong>Funktion</strong> <strong>af</strong> ‡ere<br />

<strong>variable</strong><br />

Preben Alsholm<br />

<strong>Taylorpolynomier</strong><br />

De…nition <strong>af</strong><br />

Taylorpolynomium<br />

Udledning <strong>af</strong> formlen<br />

for Taylorpolynomiet<br />

Formlen for<br />

Taylorpolynomiet<br />

Eksempel 4.8.2 i<br />

Adams<br />

<strong>Funktion</strong> givet ved<br />

simpel forskrift<br />

<strong>Funktion</strong> givet ved<br />

di¤erentialligning<br />

Taylors formel med<br />

Lagrange’s restled<br />

Vurdering <strong>af</strong> fejlen<br />

ved Taylors formel I<br />

Vurdering <strong>af</strong> fejlen<br />

ved Taylors formel II<br />

Store O-notationen<br />

<strong>Funktion</strong> <strong>af</strong> ‡ere<br />

<strong>variable</strong>

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