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Taylorpolynomier Funktion af flere variable

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Formlen for Taylorpolynomiet<br />

I Generelt fås altså<br />

således at<br />

a k = 1 k! f (k) (x 0 )<br />

P n (x) = f (x 0 ) + f 0 (x 0 ) (x x 0 ) + 1 2 f 00 (x 0 ) (x x 0 ) 2<br />

I Dette kan også skrives<br />

+ 1 3! f 000 (x 0 ) (x x 0 ) 3 + . . . + 1 n! f (n) (x 0 ) (x x 0 ) n<br />

P n (x) =<br />

n<br />

∑<br />

k=0<br />

1<br />

k! f (k) (x 0 ) (x x 0 ) k<br />

idet vi de…nerer 0! = 1 og f (0) = f .<br />

<strong>Taylorpolynomier</strong>.<br />

<strong>Funktion</strong> <strong>af</strong> ‡ere<br />

<strong>variable</strong><br />

Preben Alsholm<br />

<strong>Taylorpolynomier</strong><br />

De…nition <strong>af</strong><br />

Taylorpolynomium<br />

Udledning <strong>af</strong> formlen<br />

for Taylorpolynomiet<br />

Formlen for<br />

Taylorpolynomiet<br />

Eksempel 4.8.2 i<br />

Adams<br />

<strong>Funktion</strong> givet ved<br />

simpel forskrift<br />

<strong>Funktion</strong> givet ved<br />

di¤erentialligning<br />

Taylors formel med<br />

Lagrange’s restled<br />

Vurdering <strong>af</strong> fejlen<br />

ved Taylors formel I<br />

Vurdering <strong>af</strong> fejlen<br />

ved Taylors formel II<br />

Store O-notationen<br />

<strong>Funktion</strong> <strong>af</strong> ‡ere<br />

<strong>variable</strong>

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