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1.2.9 Racunanje vzdolzne normalne napetosti in dolocanje jedra ...

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56 1 Upogib z osno silo<br />

PREGLEDNICA 1.5 (nadaljevanje): Upogibnice <strong>in</strong> notranje sile za nekatere nosilce<br />

d) Upogibnica prostoležečega nosilca obteženega s silo F<br />

Pomik <strong>in</strong> zasuk v polju 1:<br />

w 1 =<br />

F b x (L 2 − b 2 − x 2 ), ω y1 = − F b (L 2 − b 2 − 3 x 2 ).<br />

6 L E I y 6 L E I y<br />

Pomik <strong>in</strong> zasuk v polju 2:<br />

F<br />

w 2 = ( b x(L 2 − b 2 − x 2 ) + L(x − a) 3 ),<br />

6 L E I y<br />

ω y2 = −<br />

F ( b(L 2 − b 2 − 3 x 2 ) + 3 L(x − a) 2 ).<br />

6 L E I y<br />

Pomik pri x = a ter zasuki pri x = 0, x = a <strong>in</strong> x = L:<br />

w(a) = F a2 b 2<br />

3 L E I y<br />

,<br />

ω y (0) = −<br />

F a b (L + b), ω y (a) = F a b (a − b), ω y (L) = F a b (L + a).<br />

6 L E I y 3 L E I y 6 L E I y<br />

Največji pomik, če je a > b:<br />

√ √ (L L 2 − b 2<br />

x ekst = , w ekst = F b 2 − b 2 ) 3<br />

.<br />

3<br />

3 L E I y 3<br />

Največji pomik, če je a < b:<br />

( √ )<br />

√ (L L 2 − a 2<br />

x ekst = L 1 −<br />

3 L 2 , w ekst = F a 2 − a 2 ) 3<br />

.<br />

3 L E I y 3

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