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SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA

SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA

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( 2)<br />

⎛ M A − ⎜<br />

⎝ GI pI<br />

M A + M t1<br />

M A + M t1<br />

M A + M t1<br />

− M<br />

+ + +<br />

GI pII GI pIII GI pIV<br />

I = I , I = I<br />

pI<br />

M<br />

M<br />

A<br />

A<br />

→<br />

pII<br />

M<br />

=<br />

t 2<br />

I<br />

pIII<br />

pI<br />

2<br />

M t1(<br />

2I<br />

pI + I pIII )<br />

( I + I )<br />

−<br />

pI<br />

15 ⋅0,<br />

9817<br />

=<br />

2<br />

pIV<br />

pIII<br />

−10(<br />

2 ⋅0,<br />

9817 + 3,<br />

771)<br />

( 0,<br />

9817 + 3,<br />

771)<br />

Torzijski moment u presjeku C :<br />

M C = M A + M t<br />

1<br />

= 4,<br />

483 −10<br />

= −5,<br />

517kNm<br />

t 2<br />

= −4,<br />

483kNm<br />

⎞<br />

⎟ ⋅ a = 0<br />

⎟<br />

⎠<br />

Zbog djelovanja momenta MC vijci spojke su optere�eni na smicanje :<br />

M C = n ⋅ F ⋅ R<br />

n – broj vijaka<br />

F – posmi�na sila koja djeluje na jedan vijak<br />

R – krak djelovanja sile F<br />

Potreban broj vijaka u spoju :<br />

τ<br />

=<br />

s<br />

n ≥<br />

d<br />

F<br />

A<br />

v<br />

2<br />

v<br />

4F<br />

= ≤ τ 2<br />

d π<br />

4M<br />

πτ<br />

C<br />

v<br />

sdop<br />

sdop<br />

=<br />

R 0,<br />

012<br />

d v π<br />

→ F ≤ τ<br />

4<br />

2<br />

2<br />

4 ⋅5517<br />

⋅π<br />

⋅50<br />

⋅10<br />

6<br />

sdop<br />

=<br />

⋅ 0,<br />

1<br />

9,<br />

76<br />

→ n = 10vijaka<br />

49

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