SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA
SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA
SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA
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49. Zadatak<br />
Za zadani nosa� i optere�enje odrediti mjerodavan koeficijent sigurnosti prema teoriji najve�ih<br />
normalnih naprezanja u to�kama 1 i 2 presjeka I-I ako je zadano kriti�no naprezanje materijala<br />
�K.<br />
P = 30kN<br />
H = 25kN<br />
q = 15kN<br />
/ m<br />
σ<br />
ΣF<br />
R<br />
ΣM<br />
1 1,<br />
5<br />
− q ⋅1⋅<br />
+ q ⋅<br />
2 2<br />
ΣF<br />
= 0 :<br />
R<br />
x<br />
Ax<br />
Ay<br />
y<br />
− H = 0 ⇒ R<br />
A<br />
=<br />
0 :<br />
=<br />
+ R<br />
0 :<br />
B<br />
Presjek I – I :<br />
N = −25kN<br />
T = −18,<br />
125kN<br />
2<br />
Ax<br />
M = 27,<br />
1875kNm<br />
I<br />
I<br />
= H = 25kN<br />
+ P ⋅1,<br />
5 − R ⋅3<br />
= 0 ⇒ R<br />
− q ⋅ 2,<br />
5 − P = 0 ⇒ R<br />
3<br />
70 ⋅10<br />
= + 70 ⋅10<br />
⋅<br />
12<br />
6 4<br />
= 5,<br />
83⋅10<br />
mm<br />
B<br />
Ay<br />
B<br />
= 49,<br />
375kN<br />
10 ⋅100<br />
12<br />
3<br />
= 18,<br />
125kN<br />
10 ⋅ 70 ⋅5<br />
+ 10 ⋅100<br />
⋅ 60 + 20 ⋅ 40 ⋅120<br />
159500<br />
yT<br />
=<br />
= ⇒ y<br />
10 ⋅ 70 + 10 ⋅100<br />
+ 20 ⋅ 40 2500<br />
2<br />
A = 2500mm<br />
S<br />
y<br />
y<br />
W<br />
K<br />
y max<br />
y max<br />
= 320MPa<br />
=<br />
z<br />
I<br />
y<br />
max<br />
= 40 ⋅ 20 ⋅<br />
5,<br />
83⋅10<br />
=<br />
66,<br />
2<br />
T<br />
= 63,<br />
8mm<br />
40 ⋅ 20<br />
12<br />
2<br />
2<br />
( 63,<br />
8 − 5)<br />
+ + 10 ⋅100<br />
⋅ ( 63,<br />
8 − 60)<br />
+ + 40 ⋅ 20 ⋅ ( 66,<br />
2 −10)<br />
6<br />
⇒ W<br />
y max<br />
3<br />
= 88,<br />
1⋅10<br />
mm<br />
3 3<br />
( 66,<br />
2 −10)<br />
+ ( 66,<br />
2 − 20)<br />
⋅10<br />
⋅ ⇒ S = 55,<br />
6 ⋅10<br />
mm<br />
3<br />
66,<br />
2 − 20<br />
2<br />
y<br />
y max<br />
T<br />
40<br />
2<br />
1<br />
30 10 30<br />
70 mm<br />
z<br />
3<br />
20<br />
100<br />
10<br />
130<br />
2<br />
78