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SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA

SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA

SKRIPTA RIJEÅ ENIH ZADATAKA IZ OTPORNOSTI MATERIJALA

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45. Zadatak<br />

Za zadani nosa� i optere�enje odrediti maksimalna normalna i posmi�na naprezanja u visini osi<br />

“z“te smjer i veli�inu glavnih naprezanja u to�ki 3 popre�nog presjeka nad ležajem B.<br />

Položaj težišta popre�nog presjeka nosa�a :<br />

⎛10 ⋅ 60 ⎞<br />

20 ⋅ 60 ⋅ 70 + 2⎜<br />

⎟ ⋅ 40 + 10 ⋅ 60 ⋅30<br />

∑ Ai<br />

yi<br />

2<br />

126000<br />

yT<br />

= =<br />

⎝ ⎠<br />

= = 52,<br />

5cm<br />

∑ Ai<br />

⎛10 ⋅ 60 ⎞<br />

2400<br />

20 ⋅ 60 + 2⎜<br />

⎟ + 10 ⋅ 60<br />

⎝ 2 ⎠<br />

T ( x , y ) = T<br />

T<br />

T<br />

( 30;<br />

52,<br />

5)<br />

Moment površine drugog reda :<br />

I<br />

I<br />

I<br />

z<br />

z<br />

z<br />

= I<br />

z1<br />

+ A y<br />

60 ⋅ 20<br />

=<br />

12<br />

1<br />

3<br />

2<br />

1<br />

+ 2<br />

4<br />

2 ( I + A y )<br />

z2<br />

+ 60 ⋅ 20 ⋅<br />

4<br />

= 110,<br />

5⋅10<br />

cm<br />

Reakcije i unutarnje sile :<br />

∑ F<br />

F<br />

= 0 → F<br />

+ F<br />

= 2F<br />

+ qb − F<br />

2<br />

2<br />

+ I<br />

z3<br />

2 ( 70 − 52,<br />

5)<br />

+ 2⎜<br />

+ ⋅ 60 − 52,<br />

5 ⎟ + + 10 ⋅ 60 ⋅ ( 30 − 52,<br />

5)<br />

8<br />

= 110,<br />

5⋅10<br />

mm<br />

− 2F<br />

− q ⋅b<br />

= 0<br />

4<br />

+ A<br />

3<br />

y<br />

2<br />

3<br />

⎛10<br />

⋅ 60<br />

⎜<br />

⎝<br />

36<br />

b<br />

∑<br />

M B = 0 → FA<br />

⋅3a<br />

− F ⋅ 2a<br />

− F ⋅ a + q ⋅b<br />

⋅ = 0<br />

2<br />

2<br />

b<br />

3Fa<br />

− q<br />

F<br />

2<br />

A =<br />

3a<br />

2<br />

3<br />

3⋅100<br />

⋅ 2 − 40<br />

=<br />

2<br />

3⋅<br />

2<br />

→ FA<br />

= 70kN<br />

B<br />

y<br />

A<br />

A<br />

B<br />

= 2 ⋅100<br />

+ 40 ⋅3<br />

− 70 → F<br />

B<br />

3<br />

10 ⋅ 60<br />

2<br />

= 250kN<br />

⎛ 2<br />

⎜<br />

⎝ 3<br />

⎞<br />

⎟<br />

⎠<br />

2<br />

⎞<br />

⎟<br />

⎠<br />

10 ⋅ 60<br />

12<br />

3<br />

67<br />

2

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