• Knotenspannungsverfahren – Spannungsquellen ⇒ Stromquellen ...

• Lösungen Beispiel 1:
Un 1 = −3.4154 V
Un 2 = −1.1077 V
Un 3 = −1.7231 V
1 __
/| \
| 2---3
\| /
BZK
U R1 = −2.3077 V, U R2 = −1.1077 V, U R3 = −1.6923 V
U R4 = −1.7231 V, U R5 = −4.3846 V
P q = −4.3846 W, P 0 = −6.8308 W
• Lösungen Beispiel 2:
a.) aU kl = 7.869 V, I = 0.01574 A
Un 1 = 2.951 V
Un 2 = 8.656 V
Un 3 = 0.786 V
b.) bU kl = 12.63 V, I = 0.02526 A
Un 1 = 12 V
Un 2 = 13.9 V
Un 3 = 1.263 V
/---\
1----2--
| |
BZK----3
/---\
1----2--
| |
BZK----3
• Lösungen Beispiel 3:
U kl = 3.165 V, I = 0.158 A
Un 1 = −11.2518 V
Un 2 = 3.4820 V
Un 3 = 3.1655 V
Un 4 = 1.3813 V
1--2--3
| |
4-----BZK
\___/
P q1 = −29.4676 W, P q2 = −37.8993 W, P q3 = −9.2374 W
P R1 = 27.1357 W, P R2 = 39.8988 W, P R3 = 7.1108 W
P R4 = 1.9080 W, P R5 = 0.0501 W, P Last = 0.5010 W