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Discontinuous Galerkin methods Lecture 3 - Brown University

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Let us also consider a slightly more complicated problem, originating<br />

Linear systems and fluxes -- an example<br />

electromagnetics.<br />

2.5 Exercises 39<br />

Example Consider 2.6. Consider Maxwell’s the equations<br />

one-dimensional Maxwell’s equations<br />

<br />

1<br />

ε(x) 0 ∂ E 01 ∂ E<br />

{{ZH}} + +<br />

=0. (2.2<br />

{{Z}}<br />

0 µ(x) ∂t H 10 ∂x H<br />

1<br />

2 [[E]]<br />

<br />

, E ∗ = 1<br />

<br />

{{YE}} +<br />

{{Y }}<br />

1<br />

2 [[H]]<br />

or<br />

H<br />

<br />

,<br />

∗ = 1<br />

<br />

{{ZH}} +<br />

{{Z}}<br />

1<br />

2 [[E]]<br />

<br />

, E ∗ = 1<br />

<br />

{{Y }}<br />

where<br />

Z ± <br />

µ ±<br />

=<br />

ε ± =(Y ± ) −1 ,<br />

2.5 Exercises 39<br />

Here (E, H) = (E(x, t),H(x, t)) represent the electric and magnetic fiel<br />

respectively, while ε and µ are the electric and magnetic material propertie<br />

known as permittivity and permeability, respectively.<br />

To simplify the notation, let us write this as<br />

Q ∂q<br />

+ A∂q<br />

∂t ∂x =0,<br />

or<br />

H<br />

where<br />

<br />

ε(x) 0<br />

01 E<br />

Q =<br />

, A = , q = ,<br />

0 µ(x) 10 H<br />

reflect the spatially varying material coefficients, the one-dimensional rotatio<br />

operator, and the vector of state variables, respectively.<br />

∗ = 1<br />

<br />

{{ZH}} +<br />

{{Z}}<br />

1<br />

2 [[E]]<br />

<br />

, E ∗ = 1<br />

<br />

{{YE}} +<br />

{{Y }}<br />

1<br />

2 [[H]]<br />

<br />

,<br />

where<br />

Z ± <br />

µ ±<br />

=<br />

ε ± =(Y ± ) −1 ,<br />

represents the impedance of the medium.<br />

If we again consider the simplest case of a continuous medium, things<br />

simplify considerably as<br />

H ∗ = {{H}} + Y<br />

2 [[E]], E∗ = {{E}} + Z<br />

2 [[H]],<br />

or<br />

H<br />

which we recognize as the Lax-Friedrichs flux since<br />

∗ = 1<br />

<br />

{{ZH}} +<br />

{{Z}}<br />

1<br />

2 [[E]]<br />

<br />

, E ∗ = 1<br />

<br />

{{Y }}<br />

where<br />

Z ± <br />

µ ±<br />

=<br />

ε ± =(Y ± ) −1 ,<br />

represents the impedance of the medium.<br />

If we again consider the simplest case of a cont<br />

simplify considerably as<br />

H ∗ = {{H}} + Y<br />

2 [[E]], E∗ Z<br />

= {{E}} +<br />

± <br />

µ ±<br />

=<br />

ε ± =(Y ± ) −1 ,<br />

the impedance of the medium.<br />

again consider the simplest case of a continuous medium, things<br />

onsiderably as<br />

H ∗ = {{H}} + Y<br />

2 [[E]], E∗ = {{E}} + Z<br />

2 [[H]],<br />

recognize as the Lax-Friedrichs flux since<br />

Y Z<br />

=<br />

ε µ = 1<br />

represents the impedance of the medium.<br />

If we again consider the simplest case of a cont<br />

simplify considerably as<br />

H<br />

√ = c<br />

εµ ∗ = {{H}} + Y<br />

2 [[E]], E∗ = {{E}} +<br />

which we recognize as the Lax-Friedrichs flux since<br />

Y Z<br />

=<br />

ε µ = 1<br />

The exact same approach leads to<br />

Now assume smooth materials:<br />

√ = c<br />

εµ<br />

We have recovered isthe the LF speed flux!<br />

of light (i.e., the fastest wave speed in th<br />

−1 −1/2

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