Java IO.pdf - Nguyen Dang Binh

Java I/O
bit pattern to a particular output stream. How that bit pattern is interpreted depends on what's
connected to the other end of the stream.
Example 2.1. The AsciiChart Program
import java.io.*;
public class AsciiChart {
}
public static void main(String[] args) {
for (int i = 32; i < 127; i++) {
System.out.write(i);
// break line after every eight characters.
if (i % 8 == 7) System.out.write('\n');
else System.out.write('\t');
}
System.out.write('\n');
}
Notice the use of the char literals '\t' and '\n'. The compiler converts these to the numbers
9 and 10, respectively. When these numbers are written on the console, the console interprets
those numbers as a tab and a linefeed, respectively. The same effect could have been achieved
by writing the if clause like this:
if (i % 8 == 7) System.out.write(10);
else System.out.write(9);
Here's the output:
% java AsciiChart
! " # $ % & '
( ) * + , - . /
0 1 2 3 4 5 6 7
8 9 : ; < = > ?
@ A B C D E F G
H I J K L M N O
P Q R S T U V W
X Y Z [ \ ] ^ _
` a b c d e f g
h i j k l m n o
p q r s t u v w
x y z { | } ~
%
The write() method can throw an IOException, so you'll need to wrap most calls to this
method in a try/catch block, or declare that your own method throws IOException. For
example:
try {
for (int i = 32; i