11DIFFERENTIATION - Department of Mathematics
11DIFFERENTIATION - Department of Mathematics
11DIFFERENTIATION - Department of Mathematics
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Average Cost<br />
Function<br />
EXAMPLE 3<br />
SOLUTION ✔<br />
A VERAGE C OST F UNCTIONS<br />
11.4 MARGINAL FUNCTIONS IN ECONOMICS 737<br />
Let’s now introduce another marginal concept closely related to the marginal<br />
cost. Let C(x) denote the total cost incurred in producing x units <strong>of</strong> a certain<br />
commodity. Then the average cost <strong>of</strong> producing x units <strong>of</strong> the commodity is<br />
obtained by dividing the total production cost by the number <strong>of</strong> units produced.<br />
This leads to the following definition.<br />
Suppose C(x) is a total cost function. Then the average cost function, denoted<br />
by C(x) (read ‘‘C bar <strong>of</strong> x’’), is<br />
C(x)<br />
x<br />
The derivative C(x) <strong>of</strong> the average cost function, called the marginal average<br />
cost function, measures the rate <strong>of</strong> change <strong>of</strong> the average cost function with<br />
respect to the number <strong>of</strong> units produced.<br />
The total cost <strong>of</strong> producing x units <strong>of</strong> a certain commodity is given by<br />
dollars.<br />
C(x) 400 20x<br />
a. Find the average cost function C.<br />
b. Find the marginal average cost function C.<br />
c. Interpret the results obtained in parts (a) and (b).<br />
a. The average cost function is given by<br />
C(x) C(x) 400 20x<br />
<br />
x x<br />
20 400<br />
x<br />
b. The marginal average cost function is<br />
C(x) 400<br />
x 2<br />
c. Since the marginal average cost function is negative for all admissible values<br />
<strong>of</strong> x, the rate <strong>of</strong> change <strong>of</strong> the average cost function is negative for all x 0;<br />
that is, C(x) decreases as x increases. However, the graph <strong>of</strong> C always lies<br />
(4)