11DIFFERENTIATION - Department of Mathematics
11DIFFERENTIATION - Department of Mathematics
11DIFFERENTIATION - Department of Mathematics
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EXAMPLE 4<br />
SOLUTION ✔<br />
EXAMPLE 5<br />
SOLUTION ✔<br />
FIGURE 11.14<br />
The CPI <strong>of</strong> a certain economy from year a<br />
to year b is given by I(t).<br />
I(t)<br />
a b<br />
t<br />
11.5 HIGHER-ORDER DERIVATIVES 753<br />
Refer to the example on page 621. The distance s (in feet) covered by a<br />
maglev moving along a straight track t seconds after starting from rest is given<br />
by the function s 4t 2 (0 t 10). What is the maglev’s acceleration at the<br />
end <strong>of</strong> 30 seconds?<br />
The velocity <strong>of</strong> the maglev t seconds from rest is given by<br />
v ds d<br />
<br />
dt dt (4t 2 ) 8t<br />
The acceleration <strong>of</strong> the maglev t seconds from rest is given by the rate <strong>of</strong><br />
change <strong>of</strong> the velocity <strong>of</strong> t—that is,<br />
a d d<br />
v <br />
dt dtds <br />
dt d 2s d<br />
(8t) 8<br />
2 dt dt<br />
or 8 feet per second per second, normally abbreviated, 8 ft/sec2 . <br />
Aball is thrown straight up into the air from the ro<strong>of</strong> <strong>of</strong> a building. The<br />
height <strong>of</strong> the ball as measured from the ground is given by<br />
s 16t 2 24t 120<br />
where s is measured in feet and t in seconds. Find the velocity and acceleration<br />
<strong>of</strong> the ball 3 seconds after it is thrown into the air.<br />
The velocity v and acceleration a <strong>of</strong> the ball at any time t are given by<br />
v ds d<br />
<br />
dt dt (16t2 24t 120) 32t 24<br />
and<br />
a d 2t d<br />
2 dt dtds <br />
dt d<br />
(32t 24) 32<br />
dt<br />
Therefore, the velocity <strong>of</strong> the ball 3 seconds after it is thrown into the air is<br />
v 32(3) 24 72<br />
That is, the ball is falling downward at a speed <strong>of</strong> 72 ft/sec. The acceleration<br />
<strong>of</strong> the ball is 32 ft/sec2 downward at any time during the motion. <br />
Another interpretation <strong>of</strong> the second derivative <strong>of</strong> a function—this time<br />
from the field <strong>of</strong> economics—follows. Suppose the consumer price index (CPI)<br />
<strong>of</strong> an economy between the years a and b is described by the function I(t)<br />
(a t b) (Figure 11.14). Then, the first derivative <strong>of</strong> I, I(t), gives the rate<br />
<strong>of</strong> inflation <strong>of</strong> the economy at any time t. The second derivative <strong>of</strong> I, I(t),<br />
gives the rate <strong>of</strong> change <strong>of</strong> the inflation rate at any time t. Thus, when the<br />
economist or politician claims that ‘‘inflation is slowing,’’ what he or she is<br />
saying is that the rate <strong>of</strong> inflation is decreasing. Mathematically, this is equivalent<br />
to noting that the second derivative I(t) is negative at the time t under<br />
consideration. Observe that I(t) could be positive at a time when I(t) is<br />
negative (see Example 6). Thus, one may not draw the conclusion from the<br />
aforementioned quote that prices <strong>of</strong> goods and services are about to drop!