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11DIFFERENTIATION - Department of Mathematics

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766 11 DIFFERENTIATION<br />

Solving Related Rates<br />

Problems<br />

EXAMPLE 8<br />

FIGURE 11.17<br />

The rate at which x is changing with respect<br />

to time is related to the rate <strong>of</strong> change <strong>of</strong><br />

y with respect to time.<br />

1. Assign a variable to each quantity. Draw a diagram if needed.<br />

2. Write the given values <strong>of</strong> the variables and their rates <strong>of</strong> change with respect<br />

to t.<br />

3. Find an equation giving the relationship between the variables.<br />

4. Differentiate both sides <strong>of</strong> this equation implicitly with respect to t.<br />

5. Replace the variables and their derivatives by the numerical data found in<br />

step 2 and solve the equation for the required rate <strong>of</strong> change.<br />

At a distance <strong>of</strong> 4000 feet from the launch site, a spectator is observing a<br />

rocket being launched. If the rocket lifts <strong>of</strong>f vertically and is rising at a speed<br />

<strong>of</strong> 600 feet/second when it is at an altitude <strong>of</strong> 3000 feet, how fast is the distance<br />

between the rocket and the spectator changing at that instant?<br />

SOLUTION ✔ Step 1 Let<br />

y the altitude <strong>of</strong> the rocket<br />

x the distance between the rocket and the spectator<br />

at any time t (Figure 11.17).<br />

x<br />

4000 ft<br />

Rocket<br />

Step 2 We are given that at a certain instant <strong>of</strong> time<br />

y 3000 and<br />

dy<br />

600<br />

dt<br />

Step 3<br />

and are asked to find dx/dt at that instant.<br />

Applying the Pythagorean theorem to the right triangle in Figure<br />

11.17, we find that<br />

x2 y2 40002 Therefore, when y 3000,<br />

y<br />

Launching pad<br />

x 3000 2 4000 2 5000

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