View PDF - Project Euclid
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446 PHILLIP A. GRIFFITHS<br />
I (2.2) n(LCqC)dL= I F*(o)2/ (-O12),<br />
and we shall evaluate the right hand side by integration over the fibre. For this<br />
it is convenient to parametrize C by arc length; i.e., to give C by a vectorvalued<br />
function x(s) where x’(s)l] 1. The Fr6n6t frame is defined by<br />
dx * *<br />
(.O le<br />
de* * *<br />
0.) 12e2<br />
where o* ds and O*lZ (s)ds with (s) being the curvature. (z) The fibre<br />
7r-l(x(s)) consists of lines whose frames are {x; e, e} where<br />
as pictured by<br />
x x(s)<br />
el= cos0e* + sin0e<br />
e2 -sin 0 e*l + cos 0 e*z<br />
Using (0, s) as coordinates on B (and dropping reference to F*), we have<br />
O01 (dx, el) cos 0 ds,<br />
019.<br />
(de1, ez)<br />
(-sin 0 e*l + cos 0 e, ez)dO mod ds<br />
dO mod ds.<br />
Thus dL cos 0 dO/ ds, and the right hand side of (2.2) is (a)<br />
Ic (I0 ,cos OldO)ds=2 le ds<br />
2/(C),