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Book of Proof - Amazon S3

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153<br />

S 1 : 1 = 1 2<br />

S 2 : 1 + 3 = 2 2<br />

S 3 : 1 + 3 + 5 = 3 2<br />

.<br />

.<br />

S n : 1 + 3 + 5 + 7 + ··· + (2n − 1) = n 2<br />

.<br />

.<br />

Our question is: Are all <strong>of</strong> these statements true?<br />

Mathematical induction is designed to answer just this kind <strong>of</strong> question.<br />

It is used when we have a set <strong>of</strong> statements S 1 , S 2 , S 3 ,..., S n ,..., and we<br />

need to prove that they are all true. The method is really quite simple.<br />

To visualize it, think <strong>of</strong> the statements as dominoes, lined up in a row.<br />

Imagine you can prove the first statement S 1 , and symbolize this as<br />

domino S 1 being knocked down. Additionally, imagine that you can prove<br />

that any statement S k being true (falling) forces the next statement S k+1<br />

to be true (to fall). Then S 1 falls, and knocks down S 2 . Next S 2 falls and<br />

knocks down S 3 , then S 3 knocks down S 4 , and so on. The inescapable<br />

conclusion is that all the statements are knocked down (proved true).<br />

The Simple Idea Behind Mathematical Induction<br />

S 1 S 2 S 3 S 4 S 5 S 6 ··· S k S k+1 S k+2 S k+3 S k+4 ···<br />

Statements are lined up like dominoes.<br />

S 2 S 3 S 4 S 5 S 6 ··· S k S k+1 S k+2 S k+3 S k+4 ···<br />

(1) Suppose the first statement falls (i.e. is proved true);<br />

···<br />

S k+2 S k+3 S k+4 ···<br />

S 1<br />

S k<br />

S k+1<br />

S1<br />

S2<br />

<strong>S3</strong><br />

S4<br />

S5<br />

S6<br />

(2) Suppose the k th falling always causes the (k + 1) th to fall;<br />

S1<br />

S2<br />

<strong>S3</strong><br />

S4<br />

S5<br />

S6<br />

···<br />

Sk<br />

S k+1<br />

S k+2<br />

S k+3<br />

···<br />

Then all must fall (i.e. all statements are proved true).

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