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Book of Proof - Amazon S3

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298 Solutions<br />

7. Prove or disprove: If there is a injection f : A → B and a surjection g : A → B,<br />

then there is a bijection h : A → B.<br />

This is true. Here is an outline <strong>of</strong> a pro<strong>of</strong>. Define a function g ′ : B → A as<br />

follows. For each b ∈ B, choose an element x b ∈ g −1 ({x}). (That is, choose an<br />

element x b ∈ A for which g(x b ) = b. Now let g ′ : B → A be the function defined<br />

as g ′ (b) = x b . Check that g ′ is injective and apply the the Cantor-Bernstein-<br />

Schröeder theorem.

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