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Book of Proof - Amazon S3

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78 Counting<br />

coefficients 1 2 1. Similarly (x+ y) 3 = 1x 3 +3x 2 y+3xy 2 +1y 3 , and Row 3 lists<br />

the coefficients 1 3 3 1. Pascal’s triangle is shown on the left <strong>of</strong> Figure 3.3,<br />

and immediately to the right <strong>of</strong> each Row n is listed the expansion <strong>of</strong><br />

(x + y) n . In every case (at least as far as you care to check) the numbers in<br />

Row n match up with the coefficients <strong>of</strong> (x + y) n .<br />

In fact this turns out to be true for every n. This result is known as<br />

the binomial theorem, and it is worth mentioning here. It tells how to<br />

raise a binomial x + y to a non-negative integer power n.<br />

Theorem 3.1 (Binomial Theorem) If n is a non-negative integer, then<br />

(x + y) n = ( n) 0 x n + ( n) 1 x n−1 y + ( n) 2 x n−2 y 2 + ( n) 3 x n−3 y 3 + ··· + ( n<br />

)<br />

n−1 xy n−1 + ( n<br />

n)<br />

y n .<br />

For now we will be content to accept the binomial theorem without<br />

pro<strong>of</strong>. (You will be asked to prove it in an exercise in Chapter 10.) But<br />

until then you may find it useful from time to time. For instance, you<br />

can apply it if you ever need to expand an expression such as (x + y) 7 . To<br />

do this, look at Row 7 <strong>of</strong> Pascal’s triangle in Figure 3.2 and apply the<br />

binomial Theorem to get<br />

(x + y) 7 = x 7 + 7x 6 y + 21x 5 y 2 + 35x 4 y 3 + 35x 3 y 4 + 21x 2 y 5 + 7xy 6 + y 7 .<br />

Exercises for Section 3.4<br />

1. Write out Row 11 <strong>of</strong> Pascal’s triangle.<br />

2. Use the binomial theorem to find the coefficient <strong>of</strong> x 8 y 5 in (x + y) 13 .<br />

3. Use the binomial theorem to find the coefficient <strong>of</strong> x 8 in (x + 2) 13 .<br />

4. Use the binomial theorem to find the coefficient <strong>of</strong> x 6 y 3 in (3x − 2y) 9 .<br />

5. Use the binomial theorem to show ∑ n n<br />

k=0(<br />

k)<br />

= 2 n .<br />

6. Use Definition 3.2 (page 72) and Fact 1.3 (page 12) to show ∑ n n<br />

k=0(<br />

k)<br />

= 2 n .<br />

7. Use the binomial theorem to show ∑ n<br />

k=0 3k( n<br />

k)<br />

= 4 n .<br />

8. Use Fact 3.3 (page 74) to derive Equation 3.2 (page 76).<br />

9. Use the binomial theorem to show ( n<br />

(<br />

0)<br />

−<br />

n<br />

(<br />

1)<br />

+<br />

n<br />

(<br />

2)<br />

−<br />

n<br />

(<br />

3)<br />

+<br />

n<br />

)<br />

4 − ··· + (−1)<br />

n ( n<br />

n)<br />

= 0.<br />

10. Show that the formula k ( n) (<br />

k = n n−1<br />

k−1) is true for all integers n, k with 0 ≤ k ≤ n.<br />

11. Use the binomial theorem to show 9 n = ∑ n<br />

k=0 (−1)k( n<br />

k)<br />

10 n−k .<br />

12. Show that ( n k<br />

(<br />

k)(<br />

m)<br />

=<br />

n<br />

)( n−m<br />

m k−m) .<br />

13. Show that ( n<br />

(<br />

3)<br />

=<br />

2<br />

(<br />

2)<br />

+<br />

3<br />

(<br />

2)<br />

+<br />

4<br />

(<br />

2)<br />

+<br />

5<br />

) (<br />

2 + ··· + n−1<br />

)<br />

2 .

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