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Book of Proof - Amazon S3

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80 Counting<br />

We seek the number <strong>of</strong> 3-card hands that are all red or all face cards,<br />

and this number is |A ∪ B|. By Formula (3.3), |A ∪ B| = |A| + |B| − |A ∩ B|.<br />

Let’s examine |A|,|B| and |A ∩ B| separately. Any hand in A is formed<br />

by selecting three cards from the 26 red cards in the deck, so |A| = ( 26) 3 .<br />

Similarly, any hand in B is formed by selecting three cards from the 12<br />

face cards in the deck, so |B| = ( 12) 3 . Now think about A ∩ B. It contains all<br />

the 3-card hands made up <strong>of</strong> cards that are red face cards.<br />

A ∩ B =<br />

{{<br />

} {<br />

K<br />

, K<br />

, J<br />

,<br />

♥ ♦ ♥<br />

} {<br />

K<br />

, J<br />

, Q<br />

, ,<br />

♥ ♥ ♥<br />

} }<br />

Q<br />

, J<br />

, Q<br />

,...<br />

♦ ♦ ♥<br />

(Red face<br />

cards)<br />

The deck has only 6 red face cards, so |A ∩ B| = ( 6<br />

3) .<br />

Now we can answer our question. The number <strong>of</strong> 3-card hands that<br />

are all red or all face cards is |A ∪ B| = |A| + |B| − |A ∩ B| = ( 26) (<br />

3 + 12<br />

) (<br />

3 − 6<br />

)<br />

3 =<br />

2600 + 220 − 20 = 2800.<br />

There is an analogue to Equation (3.3) that involves three sets. Consider<br />

three sets A, B and C, as represented in the following Venn Diagram.<br />

C<br />

A<br />

B<br />

Using the same kind <strong>of</strong> reasoning that resulted in Equation (3.3), you can<br />

convince yourself that<br />

|A ∪ B ∪ C| = |A| + |B| + |C| − |A ∩ B| − |A ∩ C| − |B ∩ C| + |A ∩ B ∩ C|. (3.4)<br />

There’s probably not much harm in ignoring this one for now, but if you<br />

find this kind <strong>of</strong> thing intriguing you should definitely take a course in<br />

combinatorics. (Ask your instructor!)<br />

As we’ve noted, Equation (3.3) becomes |A ∪ B| = |A| + |B| if it happens<br />

that A ∩ B = . Also, in Equation (3.4), note that if A ∩ B = , A ∩ C = and<br />

B ∩ C = , we get the simple formula |A ∪ B ∪ C| = |A| + |B| + |C|. In general,<br />

we have the following formula for n sets, none <strong>of</strong> which overlap. It is<br />

sometimes called the addition principle.<br />

Fact 3.4 (Addition Principle) If A 1 , A 2 ,..., A n are sets with A i ∩ A j = <br />

whenever i ≠ j, then |A 1 ∪ A 2 ∪ ··· ∪ A n | = |A 1 | + |A 2 | + ··· + |A n |.

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