2 DGM for elliptic problems
2 DGM for elliptic problems
2 DGM for elliptic problems
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34 2 Elliptic <strong>problems</strong><br />
∫<br />
〈∇(v − I hp v)〉 · n dS = 0 ∀Γ ∈ F h , v ∈ H 2 (Ω, T h ), (2.146) A7.3<br />
Γ<br />
|I hp v − v| H q (Ω,T h ) ≤ ¯C A h µ−q |v| H µ (Ω,T h ), v ∈ H s (Ω, T h ), h ∈ (0,h (2.147) 0 ), A7.3a<br />
where µ = min(p + 1,s), q = 0,1 and ¯C A is a constant.<br />
Let u ∈ H s (Ω) (s ≥ 1 is an integer) be an exact solution of ptoblem ( 2.1)<br />
A0.1<br />
– ( 2.2). A0.2a Then, in view of ( 2.145) A7.2 and ( 2.146),<br />
A7.3<br />
B h (u − I hp u,v h ) = 0 ∀v h ∈ S h0 , (2.148) A7.4<br />
where S h0 denotes the space of piecewise constant fucntions on T h . Hence, if<br />
Π 0 is the orthogonal projection of L 2 (Ω) onto S h0 , then ( 2.96) A2.41 and ( 2.148)<br />
A7.4<br />
imply that<br />
|B h (u − I hp u,v h )| ≤ ∣ ∣ Bh (u − I hp u,v h − Π 0 v h ) ∣ ∣ +<br />
∣ ∣Bh (u − I hp u,Π 0 v h ) ∣ ∣<br />
≤ C B |||u − I hp u||| |||v h − Π 0 v h ||| ∀v h ∈ S hp . (2.149) A7.5<br />
Obviously,<br />
|u − Π 0 u| H 1 (K) = |u| H 1 (K), K ∈ T h . (2.150) A7.6a<br />
Moreover, it follows from the approximation properties ( 2.34) eq:AP that<br />
‖v − Π 0 v‖ L 2 (K) ≤ C A h K |v| H 1 (K), v ∈ H 1 (K), K ∈ T h . (2.151) A7.6<br />
Let ψ ∈ H 1 (Ω, T h ). Then, using ( eq:MTI 2.19) and ( A3.30 2.120), we find that<br />
|||ψ||| 2 = |ψ| 2 H 1 (Ω,T h ) + Jσ h(ψ,ψ)<br />
∑<br />
(2.152) A7.7<br />
≤ |v| 2 H 1 (Ω,T h ) + 2C W h −1<br />
K ‖ψ‖2 L 2 (∂K)<br />
K∈T h<br />
≤ |ψ| 2 H 1 (Ω,T h ) +2C WC M<br />
∑<br />
K∈T h<br />
(<br />
h −2<br />
K ‖ψ‖2 L 2 (K) + h−1 K ‖ψ‖ L 2 (K)|ψ| H1 (K)<br />
For v ∈ H 1 (Ω, T h ) let us set ψ := v − Π 0 v in ( 2.152). A7.7 Then from ( 2.150) A7.6a –<br />
( 2.151) A7.6 we get<br />
|||v − Π 0 v||| 2 ≤ (1 + 4CAC 2 W C M ) ∑<br />
|v| 2 H 1 (K) (2.153) A7.8<br />
K∈T h<br />
= (1 + 4C 2 AC W C M )|v| 2 H 1 (Ω,T h ) .<br />
On the other hand, if we set ψ := u − I hp u, then by ( 2.152) A7.7 and ( 2.147)<br />
A7.3a<br />
we obtain<br />
)<br />
.<br />
|||u − I hp u||| 2 ≤ ¯C 2 Ah 2µ−2 |u| 2 H µ (Ω + 4 ¯C 2 AC W C M h 2µ−2 |u| 2 H µ (Ω)<br />
= ¯C 2 A(1 + 4C W C M )h 2µ−2 |u| 2 H µ (Ω) .<br />
(2.154) A7.9