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Week 2: PN Junction Diode

Week 2: PN Junction Diode

Week 2: PN Junction Diode

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Example 1<br />

Problem: Find diode voltage for diode with given specifications<br />

Given data: I S =0.1 fA, I D = 300 µA / 1mA<br />

Assumptions: Room-temperature dc operation with V T =25mV<br />

Analysis:<br />

With I S =0.1 fA, I D = 300 µA<br />

V<br />

D<br />

= V<br />

T<br />

⎛ ⎞<br />

⎜ I ⎟<br />

ln 1+<br />

= (0.025V)ln(1+<br />

3×<br />

10 -4 ) 0.718V<br />

10 -16 A<br />

⎜ ⎟<br />

=<br />

⎜ ⎟<br />

I D<br />

A<br />

⎝ S ⎠<br />

With I D = 1 mA, I S =0.1 fA<br />

V<br />

D<br />

=0.748V<br />

ELE2110A © 2008<br />

Lecture 02 - 17

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