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Example 10<br />
Zener diode model<br />
Analysis:<br />
KCL at output node:<br />
V<br />
L<br />
− 20<br />
5000<br />
VL<br />
− 5<br />
+<br />
100<br />
+<br />
V<br />
L<br />
5000<br />
=<br />
0<br />
Problem: Find V L and I Z using the<br />
piece-wise linear model.<br />
Given data:<br />
V S =20 V, R=5 kΩ,<br />
R Z =0.1 kΩ, V Z =5 V<br />
I<br />
Z<br />
∴ V =5.19V L<br />
V −5<br />
= L = 5.19 − 1.9mA 0<br />
100 100 5 = ><br />
<strong>Diode</strong> is actually operating in<br />
breakdown region as assumed.<br />
ELE2110A © 2008<br />
Lecture 02 - 47
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