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Example 7 (Cont.)<br />
The second guess is D 1<br />
off and D 2 on:<br />
Since I D2 = I 1 ,<br />
15−(<br />
−10)<br />
I =<br />
1 10kΩ+<br />
5kΩ<br />
= 1.67mA<br />
V = 15−10,000I<br />
=−1.67V<br />
D1<br />
1<br />
Q-points are D 1 : (0 mA, -1.67 V): off<br />
D 2 : (1.67 mA, 0 V) : on<br />
This is consistent with our assumptions and analysis is finished.<br />
ELE2110A © 2008<br />
Lecture 02 - 41
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