Week 2: PN Junction Diode

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Current for Three Different Values of I S I =10 I = 100I SA SB SC i D = I S ⎛ v exp ⎜ ⎝ V D T ⎞ ⎟ ⎠ Let i DA =i DB i i SA SB = ⎛ v ⎞ DB − vDA exp ⎜ ⎟ = 10 ⎝ VT ⎠ v DB − v DA = V T ln10 ≈ 60 mV ELE2110A © 2008 Lecture 02 - 20
Topics to cover… • Physical operation of pn junction diode • Terminal I-V characteristics • Breakdown and junction capacitances • <strong>Diode</strong> circuits analysis ELE2110A © 2008 Lecture 02 - 21
Page 1 and 2: ELE 2110A Electronic Circuits Week
Page 3 and 4: Why diodes? • R, C, L are linear
Page 5 and 6: Physical Structure of pn Junction D
Page 7 and 8: Diffusion of Electrons and Holes
Page 9 and 10: Built-in Electric Field Charge Dens
Page 11 and 12: Width of Depletion Region Charge De
Page 13 and 14: Reverse-Biased PN Junction Reverse
Page 15 and 16: Diode Terminal I-V Characteristics
Page 17 and 18: Example 1 Problem: Find diode volta
Page 19: Semi-log Plot of Diode Current i D
Page 23 and 24: Breakdown Mechanism 1: Avalanche Br
Page 25 and 26: pn Junction Capacitance: Reverse Bi
Page 27 and 28: pn Junction Capacitance: Forward Bi
Page 29 and 30: Topics to cover… • Physical ope
Page 31 and 32: Load-Line Analysis (Example 2) Prob
Page 33 and 34: Newton’s Iteration Method for f (
Page 35 and 36: Analysis using Ideal Diode Model Id
Page 37 and 38: Example 5 Since source is forcing c
Page 39 and 40: Example 6 Analysis: Since 10V sourc
Page 41 and 42: Example 7 (Cont.) The second guess
Page 43 and 44: Zener Diode Circuit Analysis (Examp
Page 45 and 46: Zener Diode Applications: Voltage R
Page 47 and 48: Example 10 Zener diode model Analys

Week 2: PN Junction Diode

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