Week 2: PN Junction Diode

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Zener <strong>Diode</strong> Circuit Analysis (Example 9) Using piecewise linear model: I Z = −I >0 D Assume in breakdown region −20+ 5100I + 5= 0 Z (20−5)V I = = 2.94mA Z 5100Ω Since I Z >0 (I D
Zener <strong>Diode</strong> Applications: Voltage Regulator ELE2110A © 2008 Lecture 02 - 45
Page 1 and 2: ELE 2110A Electronic Circuits Week
Page 3 and 4: Why diodes? • R, C, L are linear
Page 5 and 6: Physical Structure of pn Junction D
Page 7 and 8: Diffusion of Electrons and Holes
Page 9 and 10: Built-in Electric Field Charge Dens
Page 11 and 12: Width of Depletion Region Charge De
Page 13 and 14: Reverse-Biased PN Junction Reverse
Page 15 and 16: Diode Terminal I-V Characteristics
Page 17 and 18: Example 1 Problem: Find diode volta
Page 19 and 20: Semi-log Plot of Diode Current i D
Page 21 and 22: Topics to cover… • Physical ope
Page 23 and 24: Breakdown Mechanism 1: Avalanche Br
Page 25 and 26: pn Junction Capacitance: Reverse Bi
Page 27 and 28: pn Junction Capacitance: Forward Bi
Page 29 and 30: Topics to cover… • Physical ope
Page 31 and 32: Load-Line Analysis (Example 2) Prob
Page 33 and 34: Newton’s Iteration Method for f (
Page 35 and 36: Analysis using Ideal Diode Model Id
Page 37 and 38: Example 5 Since source is forcing c
Page 39 and 40: Example 6 Analysis: Since 10V sourc
Page 41 and 42: Example 7 (Cont.) The second guess
Page 43: Zener Diode Circuit Analysis (Examp
Page 47 and 48: Example 10 Zener diode model Analys

Week 2: PN Junction Diode

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