Ch. 6.1 #7-49 odd

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a) That the senior owes at least $1000 X 1000 3262 2262 z 2.06 1100 1100 Pz ( 2.06) 1 0.0197 0.9803 or98.03% -2.06 0 b) That the senior owes more than $4000 X 4000 3262 738 z 0.67 1100 1100 Pz ( 0.67) 1 0.7486 0.2514 or 25.14% 0 0.67 c) That the senior owes between $3000 and $4000 X 3000 3262 262 z 0.24 1100 1100 X 4000 3262 738 z 0.67 1100 1100 P( 0.24 z 0.67) 0.7486 0.4052 0.3434 or 34.34% -0.24 0.67
15. Waiting to Be Seated The average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes, with a standard deviation of 3.6 minutes. Assume the variable is normally distributed. When a patron arrives at the restaurant for dinner, find the probability that the patron will have to wait the following time. a) Between 15 and 22 minutes X 15 23.5 8.5 z 2.36 3.6 3.6 X 22 23.5 1.5 z 0.42 3.6 3.6 P( 2.36 z 0.42) 0.3372 0.0091 0.3281 -2.36 -0.42 b) Less than 18 minutes or more than 25 minutes X 18 23.5 5.5 z 1.53 3.6 3.6 X 25 23.5 1.5 z 0.42 3.6 3.6 P( z 1.53 or z 0.42) 0.0630 (1 0.6628) 0.063 0.3372 0.4002 -1.53 0.42 c) Is it likely that a person will be seated in less than 15 minutes? X 15 23.5 8.5 z 2.36 3.6 3.6 Pz ( 2.36) 0.0091
Page 1 and 2: Ch. 6.1 #7-49 odd The area is found
Page 3 and 4: The area is found by looking up z=
Page 5 and 6: Area= 0.9591 - 0.0069 = 0.9522 Area
Page 7 and 8: c) 60.64% of the area under the dis
Page 9: . More than $40,000 a year X 40,00
Page 13 and 14: Therefore, a cutoff score of 93 wil
Page 15 and 16: x x 25,000 26,489 Z 2.79
Page 17 and 18: Pz ( 0.90) 1 0.8159 0.1841 18.41%
Page 19 and 20: q = 1-q = 1 - 0.6 = 0.4 np = (10)(0
Page 21: 11. Elementary School Teachers Wome

Ch. 6.1 #7-49 odd

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