Ch. 6.1 #7-49 odd
Ch. 6.1 #7-49 odd
Ch. 6.1 #7-49 odd
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Therefore, a cutoff score of 93 will make a student eligible for the program.<br />
23. Used Car Prices an automobile dealer finds that the average price of a previously owned vehicle is<br />
$8256. He decides to sell cars that will appeal to the middle 60% of the market in terms of price. Find the<br />
maximum and minimum prices of the cars the dealer will sell. The standard deviation is $1150, and the<br />
variable is normally distributed.<br />
$8256, $1150 . The middle 60% means that 30% of the area will be on either side of the mean.<br />
The corresponding z score is found using area = 0.20.<br />
The z scores are 0.84.<br />
Min z * 0.84*1150 8256 $7290<br />
Max z * 0.84*1150 8256 $9222<br />
26. High School Competency Test a mandatory competency test for high school sophomores has a<br />
normal distribution with a mean of 400 and a standard deviation of 100.<br />
a) The top 3% of students receive $500. What is the minimum score you would need to receive this<br />
award?<br />
400, 100<br />
10.03 0.97<br />
z 1.88<br />
Min z * 1.88*100 400 588<br />
588 is minimum score to receive the award.<br />
b) The bottom 1.5% of students must go to summer school. What is the minimum score you would need<br />
to stay out of this group?<br />
400, 100<br />
For the bottom 1.5%, the area is 0.015.<br />
z 2.17<br />
Min z * 2.17*100 400 183<br />
183 is the minimum score to avoid summer school.